Optimal. Leaf size=343 \[ \frac{3 b c-a d}{4 a^4 x^4}-\frac{c}{7 a^3 x^7}-\frac{a^2 e-3 a b d+6 b^2 c}{a^5 x}-\frac{\log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right ) \left (-2 a^3 f+14 a^2 b e-35 a b^2 d+65 b^3 c\right )}{54 a^{16/3} b^{2/3}}+\frac{\log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \left (-2 a^3 f+14 a^2 b e-35 a b^2 d+65 b^3 c\right )}{27 a^{16/3} b^{2/3}}+\frac{\tan ^{-1}\left (\frac{\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt{3} \sqrt [3]{a}}\right ) \left (-2 a^3 f+14 a^2 b e-35 a b^2 d+65 b^3 c\right )}{9 \sqrt{3} a^{16/3} b^{2/3}}-\frac{x^2 \left (-2 a^3 f+5 a^2 b e-8 a b^2 d+11 b^3 c\right )}{9 a^5 \left (a+b x^3\right )}-\frac{x^2 \left (a^3 (-f)+a^2 b e-a b^2 d+b^3 c\right )}{6 a^4 \left (a+b x^3\right )^2} \]
[Out]
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Rubi [A] time = 1.14773, antiderivative size = 343, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 8, integrand size = 30, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.267 \[ \frac{3 b c-a d}{4 a^4 x^4}-\frac{c}{7 a^3 x^7}-\frac{a^2 e-3 a b d+6 b^2 c}{a^5 x}-\frac{\log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right ) \left (-2 a^3 f+14 a^2 b e-35 a b^2 d+65 b^3 c\right )}{54 a^{16/3} b^{2/3}}+\frac{\log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \left (-2 a^3 f+14 a^2 b e-35 a b^2 d+65 b^3 c\right )}{27 a^{16/3} b^{2/3}}+\frac{\tan ^{-1}\left (\frac{\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt{3} \sqrt [3]{a}}\right ) \left (-2 a^3 f+14 a^2 b e-35 a b^2 d+65 b^3 c\right )}{9 \sqrt{3} a^{16/3} b^{2/3}}-\frac{x^2 \left (-2 a^3 f+5 a^2 b e-8 a b^2 d+11 b^3 c\right )}{9 a^5 \left (a+b x^3\right )}-\frac{x^2 \left (a^3 (-f)+a^2 b e-a b^2 d+b^3 c\right )}{6 a^4 \left (a+b x^3\right )^2} \]
Antiderivative was successfully verified.
[In] Int[(c + d*x^3 + e*x^6 + f*x^9)/(x^8*(a + b*x^3)^3),x]
[Out]
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Rubi in Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((f*x**9+e*x**6+d*x**3+c)/x**8/(b*x**3+a)**3,x)
[Out]
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Mathematica [A] time = 0.461329, size = 328, normalized size = 0.96 \[ \frac{-\frac{189 a^{4/3} (a d-3 b c)}{x^4}-\frac{108 a^{7/3} c}{x^7}-\frac{756 \sqrt [3]{a} \left (a^2 e-3 a b d+6 b^2 c\right )}{x}+\frac{84 \sqrt [3]{a} x^2 \left (2 a^3 f-5 a^2 b e+8 a b^2 d-11 b^3 c\right )}{a+b x^3}+\frac{28 \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \left (-2 a^3 f+14 a^2 b e-35 a b^2 d+65 b^3 c\right )}{b^{2/3}}+\frac{28 \sqrt{3} \tan ^{-1}\left (\frac{1-\frac{2 \sqrt [3]{b} x}{\sqrt [3]{a}}}{\sqrt{3}}\right ) \left (-2 a^3 f+14 a^2 b e-35 a b^2 d+65 b^3 c\right )}{b^{2/3}}+\frac{126 a^{4/3} x^2 \left (a^3 f-a^2 b e+a b^2 d-b^3 c\right )}{\left (a+b x^3\right )^2}+\frac{14 \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right ) \left (2 a^3 f-14 a^2 b e+35 a b^2 d-65 b^3 c\right )}{b^{2/3}}}{756 a^{16/3}} \]
Antiderivative was successfully verified.
[In] Integrate[(c + d*x^3 + e*x^6 + f*x^9)/(x^8*(a + b*x^3)^3),x]
[Out]
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Maple [B] time = 0.024, size = 611, normalized size = 1.8 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((f*x^9+e*x^6+d*x^3+c)/x^8/(b*x^3+a)^3,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((f*x^9 + e*x^6 + d*x^3 + c)/((b*x^3 + a)^3*x^8),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.222887, size = 809, normalized size = 2.36 \[ \frac{\sqrt{3}{\left (14 \, \sqrt{3}{\left ({\left (65 \, b^{5} c - 35 \, a b^{4} d + 14 \, a^{2} b^{3} e - 2 \, a^{3} b^{2} f\right )} x^{13} + 2 \,{\left (65 \, a b^{4} c - 35 \, a^{2} b^{3} d + 14 \, a^{3} b^{2} e - 2 \, a^{4} b f\right )} x^{10} +{\left (65 \, a^{2} b^{3} c - 35 \, a^{3} b^{2} d + 14 \, a^{4} b e - 2 \, a^{5} f\right )} x^{7}\right )} \log \left (\left (-a b^{2}\right )^{\frac{1}{3}} b x^{2} - a b + \left (-a b^{2}\right )^{\frac{2}{3}} x\right ) - 28 \, \sqrt{3}{\left ({\left (65 \, b^{5} c - 35 \, a b^{4} d + 14 \, a^{2} b^{3} e - 2 \, a^{3} b^{2} f\right )} x^{13} + 2 \,{\left (65 \, a b^{4} c - 35 \, a^{2} b^{3} d + 14 \, a^{3} b^{2} e - 2 \, a^{4} b f\right )} x^{10} +{\left (65 \, a^{2} b^{3} c - 35 \, a^{3} b^{2} d + 14 \, a^{4} b e - 2 \, a^{5} f\right )} x^{7}\right )} \log \left (a b + \left (-a b^{2}\right )^{\frac{2}{3}} x\right ) + 84 \,{\left ({\left (65 \, b^{5} c - 35 \, a b^{4} d + 14 \, a^{2} b^{3} e - 2 \, a^{3} b^{2} f\right )} x^{13} + 2 \,{\left (65 \, a b^{4} c - 35 \, a^{2} b^{3} d + 14 \, a^{3} b^{2} e - 2 \, a^{4} b f\right )} x^{10} +{\left (65 \, a^{2} b^{3} c - 35 \, a^{3} b^{2} d + 14 \, a^{4} b e - 2 \, a^{5} f\right )} x^{7}\right )} \arctan \left (-\frac{\sqrt{3} a b - 2 \, \sqrt{3} \left (-a b^{2}\right )^{\frac{2}{3}} x}{3 \, a b}\right ) - 3 \, \sqrt{3}{\left (28 \,{\left (65 \, b^{4} c - 35 \, a b^{3} d + 14 \, a^{2} b^{2} e - 2 \, a^{3} b f\right )} x^{12} + 49 \,{\left (65 \, a b^{3} c - 35 \, a^{2} b^{2} d + 14 \, a^{3} b e - 2 \, a^{4} f\right )} x^{9} + 18 \,{\left (65 \, a^{2} b^{2} c - 35 \, a^{3} b d + 14 \, a^{4} e\right )} x^{6} + 36 \, a^{4} c - 9 \,{\left (13 \, a^{3} b c - 7 \, a^{4} d\right )} x^{3}\right )} \left (-a b^{2}\right )^{\frac{1}{3}}\right )}}{2268 \,{\left (a^{5} b^{2} x^{13} + 2 \, a^{6} b x^{10} + a^{7} x^{7}\right )} \left (-a b^{2}\right )^{\frac{1}{3}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((f*x^9 + e*x^6 + d*x^3 + c)/((b*x^3 + a)^3*x^8),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((f*x**9+e*x**6+d*x**3+c)/x**8/(b*x**3+a)**3,x)
[Out]
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GIAC/XCAS [A] time = 0.221184, size = 586, normalized size = 1.71 \[ \frac{{\left (65 \, b^{3} c \left (-\frac{a}{b}\right )^{\frac{1}{3}} - 35 \, a b^{2} d \left (-\frac{a}{b}\right )^{\frac{1}{3}} - 2 \, a^{3} f \left (-\frac{a}{b}\right )^{\frac{1}{3}} + 14 \, a^{2} b \left (-\frac{a}{b}\right )^{\frac{1}{3}} e\right )} \left (-\frac{a}{b}\right )^{\frac{1}{3}}{\rm ln}\left ({\left | x - \left (-\frac{a}{b}\right )^{\frac{1}{3}} \right |}\right )}{27 \, a^{6}} + \frac{\sqrt{3}{\left (65 \, \left (-a b^{2}\right )^{\frac{2}{3}} b^{3} c - 35 \, \left (-a b^{2}\right )^{\frac{2}{3}} a b^{2} d - 2 \, \left (-a b^{2}\right )^{\frac{2}{3}} a^{3} f + 14 \, \left (-a b^{2}\right )^{\frac{2}{3}} a^{2} b e\right )} \arctan \left (\frac{\sqrt{3}{\left (2 \, x + \left (-\frac{a}{b}\right )^{\frac{1}{3}}\right )}}{3 \, \left (-\frac{a}{b}\right )^{\frac{1}{3}}}\right )}{27 \, a^{6} b^{2}} - \frac{22 \, b^{4} c x^{5} - 16 \, a b^{3} d x^{5} - 4 \, a^{3} b f x^{5} + 10 \, a^{2} b^{2} x^{5} e + 25 \, a b^{3} c x^{2} - 19 \, a^{2} b^{2} d x^{2} - 7 \, a^{4} f x^{2} + 13 \, a^{3} b x^{2} e}{18 \,{\left (b x^{3} + a\right )}^{2} a^{5}} - \frac{{\left (65 \, \left (-a b^{2}\right )^{\frac{2}{3}} b^{3} c - 35 \, \left (-a b^{2}\right )^{\frac{2}{3}} a b^{2} d - 2 \, \left (-a b^{2}\right )^{\frac{2}{3}} a^{3} f + 14 \, \left (-a b^{2}\right )^{\frac{2}{3}} a^{2} b e\right )}{\rm ln}\left (x^{2} + x \left (-\frac{a}{b}\right )^{\frac{1}{3}} + \left (-\frac{a}{b}\right )^{\frac{2}{3}}\right )}{54 \, a^{6} b^{2}} - \frac{168 \, b^{2} c x^{6} - 84 \, a b d x^{6} + 28 \, a^{2} x^{6} e - 21 \, a b c x^{3} + 7 \, a^{2} d x^{3} + 4 \, a^{2} c}{28 \, a^{5} x^{7}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((f*x^9 + e*x^6 + d*x^3 + c)/((b*x^3 + a)^3*x^8),x, algorithm="giac")
[Out]